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Air compressor water heater heat knowledge
Author: www.dg-zhihe.com      Release Date:2012/11/22      View Count:32542
 

 

A: kcal and Joule conversion:
The 1 card ( CAL ) =4.1868Joule ( J )1 kcal =4186.57Joule ( J )
1 kcal =1000card =0.0042=4200MJ mj.
1 degrees =1kwh kilowatt hours, according to the W=Pt=1*1=1000w *36000 seconds =3600000joule.
Two: the power consumption, power, current, voltage relationship
Power consumption of unit: kilowatt hour, ( KW· H ), referred to as" degree"
Power unit ( P ): W, referred to as w ( W )
Current ( I ) unit: ampere, referred to as the safety ( A )
Voltage ( U ) unit: V, V ( abbreviation V ), household power is generally a single phase alternating current, a voltage of 220 V; industrial power supplies is a three-phase alternating current, voltage of 380 v. 1 degrees of electricity refers to1000 watts of power using 1 hours of the consumption of electricity.
Three: you know the water each degree rise to consume the number electricity?
A ton of water equal to 1000litres of water. Though t and l is a unit of weight, is a unit of volume, but the density of water is 11litres of water are equal to one kilogram of water, so a ton of water equal to 1000litres of water. But this is only theoretical, practical is the density of the water for impurity may be a little deviation, but in general calculation can be1 tons of water is equal to1000 liters of water.
One litre of water is equal to 1 kg, which is conditional ( an atmospheric pressure,4 degrees C ), the general is not strict, the density of water is 1.00kg/L.
1kg ( L) water temperature every1 degrees higher power consumption is 0.00116 degrees ( kw )
A ton of water temperature every1 degrees higher power consumption is 1.16 degrees ( kw )
Four:1 kg water temperature1 degrees Celsius heat required approximately 1 kcal
Specific heat capacity heat Q= C×m×t Q=CxMxT temperature difference of quality
The specific heat of water c=4.2× 103 J/KG
The temperature difference is1( degrees)
The water quality of the density of m= P ×v=1.0×M=PxV×10-3=1kg, volume103(1 liters of water or 1 kg of water )
Conclusion:
Heat Q=c× m ×t=4200 × 1× 1=4.2× 103=1000card =1kcal
1kw/h produced a 860 calories
So1 litres of water temperature1 degrees C power consumption for1/860=0.00116( kw )

 

 
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