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Indoor air conditioning refrigeration system heat required
Author: www.dg-zhihe.com      Release Date:2012/11/2      View Count:21104
 
   Consumer is buying when the air conditioning, the first meet problem is, what need to buy more power (refrigeration system heat) air conditioning and the use of his room to meet requirements. If choose big cause economic waste, because the greater the power price is higher, the greater the power consumption. And choose small, inadequate, the cold not cold, this it's hot. So how to calculate the refrigeration system heat? Below introduce a simple formula, can quickly calculated each different room of the required refrigeration system heat.
   The refrigerating capacity needed: (W) = unit area refrigerating capacity required (W/m2) x room floor area (m2).
   The formula for refrigerating capacity per unit area is according to different housing structure, different floor and decide. Now to offer you an approximate algorithm for common faces south cement steel structure of the upper house for 185 ~ 195 W/m2, the middle floor is 145 ~ 155 W/m2. The summer of room temperature is higher average room appropriate chooses some bigger, and choose small (generally minimum for 145 W/m2). For example: the room of 25 m2, the floor for the sixth floor apartment buildings layer 3, then, the refrigerating capacity of the air conditioning is: 150 W/m2 × 25 m2 = 3750 W; According to 1 P = 2500 w to conversion, 3750 w = 1.5 P. If room area is unchanged, the floor for top, so, the refrigerating capacity of the air conditioning is: 190 W/m2 × 25 m2 = 4750 W, the conversion of 1.9 P. If the air conditioning is installed in the unit offices, so, must choose the refrigerating capacity per unit area required in the 200 W/m2, because many people, in and out of the frequent, plus the modern office equipment (such as computer, copy machine, and so on) the heat generated by the should be taken into consideration, such as calculated in accordance with the common housing, air conditioning refrigerating capacity of the absolute enough, this please users in the choose and buy when the air conditioning to pay attention.
   The above is the refrigerating capacity needed calculation, so, air-conditioning and heating system, how to calculate the heat? We just need to get the formula to calculate the refrigerating capacity to heat, the middle floor unit area of heat required of 220 W/m2, the top of 250 W/m2, generation into the formula can.
   It should be noted that, in all air conditioning model indicated that the power to all the refrigerating capacity for the standard, for example: KFR-25 GW 25 of the refrigerating capacity is 2500 W said; And as KFR-80 LW refrigerating capacity for the 8000 W. The heat in the manual data is out. Therefore, users buy when the air conditioning, should be with their actual use need to make the best choice. Finally have two Suggestions: 1 heating air conditioning for energy for refrigeration of 1.2 ~ 1.4 times, so, the choice model changes in temperature, please give priority to the quantity of heat to calculate. 2. Air conditioning should buy big unfavorable buy small, when buying, please choose a little greater than the calculated value of power of the model.
   Air conditioning and refrigeration (hot) area = air conditioning and refrigeration (hot) ÷ amount prescribed by the state refrigeration unit (hot) volume
The regulations of the state is to point to the air conditioning refrigerating capacity units refrigeration to ensure that every hour, every square metre 130 W refrigerating capacity in between 180- W.
   The regulations of the state is to point to the air conditioning system heat heating to ensure that every hour of every square metre 180 W heat in between-250 W.
As for the interval value how to selected major see several aspects: A, B, whether the top floor, whether there is A western, C, seal degree, D, room window size, E, floor height, F, other factors if these factors have, so whether the heat or the refrigerating capacity must choose maximum.
 
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